![]() So using the solve block sure should be an option. Nevertheless its usually not that good an idea to use symbolics when you actually are not looking for a symbolic result but just for a numeric value. So turning on this option seems to have done the job, Now that I turned on this option once again for the screenshot, assigning the result to a variable and numerically evaluating it worked OK. ![]() ![]() Sometimes it helps, but in your case it doesn't.ĮDIT: Looks I made a mistake in the first place when I tried. There is a calculation option you should turn on: If you try to evaluate that expression by following the symbolic evaluation with a numeric evaluation ("=") you get an error, because the numerics does not know the variables (which actually should be units). The symbolics does not know anything about units and you can see in the result that units are not labelled correctly - thy should be bold and blue but as can be seen they are black (variables). The use of the symbolic "solve" command fails, because the third party symbolic is not as good integrated into Prime as we would wish. You have to use the Boolean / comparison = and not the assignment ":=". Of course you can do so for all six functions and plot them all in one plot.Īs for R.h1 - both ways you tried are correct apart from using the wrong "=" in the solve block. Furthermore I used the if-function to force the horizontal line for the first five minutes as seen in he Word document. You can define a function as seen in the pic below. You correctly calculated the coefficients for the third order polynomials in ln(x), but you never used them!
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |